How can I apply the Leibniz test if an alternating series doesn't decrease?
#1
I’ve been working through some problems on the convergence of infinite series, and I keep getting stuck when a series has terms that alternate in sign but don’t strictly decrease in absolute value from the very first term. It makes applying the Leibniz test for alternating series feel a bit shaky to me.
Reply
#2
Yeah I ran into this last semester. If a_n is positive and goes to 0 but isn’t decreasing from the first term, it’s enough to know it is eventually decreasing. Once you reach some N so that a_{n+1} <= a_n for all n >= N and a_n -> 0, the alternating series test tells you the tail converges, and the finite head doesn’t affect convergence.
Reply
#3
I had a series where the terms bounced around at the start. I checked the tail from N=10 where it settled, and the partial sums of (-1)^n a_n from there looked stable; the full sum seemed to converge, but I wasn’t sure about the early terms.
Reply
#4
Do you sometimes worry the problem is actually about whether the convergence is conditional rather than absolute, or about applying a rearrangement or a Dirichlet style test?
Reply
#5
I tried a grouping trick once, pairing terms: write (-1)^n a_n as (a_{2k}-a_{2k+1}) and see if the pairwise sum converges. It helped in some cases, but not all, and I ended up stuck again.
Reply


[-]
Quick Reply
Message
Type your reply to this message here.

Image Verification
Please enter the text contained within the image into the text box below it. This process is used to prevent automated spam bots.
Image Verification
(case insensitive)

Forum Jump: